-0.1x^2+115x-2750=0

Solution for -0.1x^2+115x-2750=0 equation:

-0.1x^2+115x-2750=0

a = -0.1; b = 115; c = -2750;
Δ = b2-4ac
Δ = 1152-4·(-0.1)·(-2750)
Δ = 12125
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{12125}=\sqrt{25*485}=\sqrt{25}*\sqrt{485}=5\sqrt{485}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(115)-5\sqrt{485}}{2*-0.1}=\frac{-115-5\sqrt{485}}{-0.2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(115)+5\sqrt{485}}{2*-0.1}=\frac{-115+5\sqrt{485}}{-0.2}
$